-1-5[4+2(c-3)]=2(c+1)

Solution for -1-5[4+2(c-3)]=2(c+1) equation:

Simplifying
-1 + -5[4 + 2(c + -3)] = 2(c + 1)

Reorder the terms:
-1 + -5[4 + 2(-3 + c)] = 2(c + 1)
-1 + -5[4 + (-3 * 2 + c * 2)] = 2(c + 1)
-1 + -5[4 + (-6 + 2c)] = 2(c + 1)

Combine like terms: 4 + -6 = -2
-1 + -5[-2 + 2c] = 2(c + 1)
-1 + [-2 * -5 + 2c * -5] = 2(c + 1)
-1 + [10 + -10c] = 2(c + 1)

Combine like terms: -1 + 10 = 9
9 + -10c = 2(c + 1)

Reorder the terms:
9 + -10c = 2(1 + c)
9 + -10c = (1 * 2 + c * 2)
9 + -10c = (2 + 2c)

Solving
9 + -10c = 2 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
9 + -10c + -2c = 2 + 2c + -2c

Combine like terms: -10c + -2c = -12c
9 + -12c = 2 + 2c + -2c

Combine like terms: 2c + -2c = 0
9 + -12c = 2 + 0
9 + -12c = 2

Add '-9' to each side of the equation.
9 + -9 + -12c = 2 + -9

Combine like terms: 9 + -9 = 0
0 + -12c = 2 + -9
-12c = 2 + -9

Combine like terms: 2 + -9 = -7
-12c = -7

Divide each side by '-12'.
c = 0.5833333333

Simplifying
c = 0.5833333333